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My intuition says that both approaches, discrete time models and continuous time models will be models (i.e. approximations) of reality. Therefore it should be possible to develop useful models in both domains.

Continuous time models have more mathematical elegance and can therefore probably bring more mathematical machinery to bear on the problem which presumably helps with deriving analytical solutions and asymptotic limits.

Discrete models more easily correspond to observed data and measurements and are easier to simulate on computers.

I have been told that it is possible to discretise continuous time models and vice-versa but care has to be taken when performing this transformation. Could you please highlight what the common pitfalls are, in particular when modelling asset prices? If there are other differences in the dynamics between the two approaches (for example possibly something like non-linearities, chaos, ... in one and not the other) then I would like to know about that as well.

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I mainly speak as market practitioner when I say that I believe in the end all models that are applied to data and real life pricing issues are discretized. Think about it, even the BS hedge argument is in the end just a "theoretical continuous time overlay" of actual discrete time steps and re-hedges. Thus some of the limiting assumptions re BS. You do not have continuous prices, even if ticks come in millisecond frequency they are still discretely timed. Thus you cannot hedge continuously but only re-hedge when you receive new price discovery.

Continuous pricing models are elegant to work with from a mathematical standpoint. However, in the end whatever derivative or mortgage security you attempt to price you must resort to discretized version of pricing algorithms. Thats my take of it. I would not waste too much time on trying to figure out how to move from one version to the other. I rather recommend you think about the problem at hand and what you actually want to solve for. From my experience 90% of pricing complexities boil down to finding a replication of the to-be-price asset in question. Monte Carlo simulators have become my best friend because their applicability is so versatile.

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The fact that in practice all models become discrete doesn't imply the question is not important, even from the application point of view. For example, a question that steams from the OP's question is whether a pricing from a multi-period discrete model converges to that of a continuous one. –  Mlazhinka Shung Gronzalez LeWy Jul 9 '14 at 16:54
Sure if you make the steps sufficiently small, else by definition 2 models (1 discrete, 1 continuous) are not exchangeable. And I never questioned the validity of the question itself. Academicians should occupy all their time with this issue, I prefer to have my juniors focus on working the other way around: Pricing is known for assets of specific properties, if a continuous model exists and arrives at such pricing then great, else let's not waste time, wrap up the sleeves and create a discrete model that can properly price the asset at hand. –  Matt Wolf Jul 10 '14 at 11:48
One thing that I am not sure if we are both taking into account is that it is not the same thing (1) a discretization of a continuous model and (2) a discrete model (as in a multi-period discrete model). There is a claim in Hunt & Kennedy's book that I don't have enough knowledge to justify that says "Though of mathematical interest, the [discrete] multi-period case is not important in practice and when we again take up the story of derivative pricing in Chapter 7 we will work entirely in the continuous time setting." –  Mlazhinka Shung Gronzalez LeWy Jul 10 '14 at 14:11
In other words, they are saying that, in practice, what is more useful is continuous models. Of course, for actually computing discretizations of continuous models. A question that I have myself is: If one applies no-arbitrage pricing to multi-period discrete models and take limit as the number of periods tends to infinity, do we get the same price as with the no-arbitrage price for a continuous model? –  Mlazhinka Shung Gronzalez LeWy Jul 10 '14 at 14:15
For most exotic derivatives numerical methods do not exist. You generally end up with some sort of discretization. But in either case taking into account no-arbitrage conditions, a discrete and continuous model must agree on price else the models are not identical and one of the two is wrong. I argue that you can price any derivative with a discrete model but only very few can be priced with continuous models. And to answer your last question (unless I misunderstand your question), absolutely yes, else the models would not agree. –  Matt Wolf Jul 10 '14 at 15:59

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