# Distribution of hitting time of the integrated CIR process

If an increasing process $X_t$ has a known Laplace transform $\mathbb{E} e^{-s X_t} = m_t(s)$, define its hitting time $\tau$ to some level $B$ to be $$\tau = \inf\{ u > 0 : X_u \geq B \}.$$ Can we express the Laplace transform (or its CDF) of $\tau$ in terms of $m$?

In particular, I am interested in the hitting time of the integrated CIR process $$X_t = \int_0^t V_s \ ds$$ where $$dV_t = (\alpha V_t + \beta) dt + \gamma \sqrt{V_t} dW_t.$$ The Laplace transform of $X_t$ is known in closed-form in this case, and given by $$m_t(s) = \mathbb{E} e^{-s X_t} = \left( \frac{e^{-\alpha t/2}}{\cosh(Pt/2)-\frac{\alpha}{P}\sinh(Pt/2)} \right)^{2\beta/\gamma^2} \exp\left(-\frac{s V_0}{P} \frac{2 \sinh(Pt/2)}{\cosh(Pt/2)-\frac{\alpha}{P} \sinh(Pt/2)}\right)$$ where $P = \sqrt{\alpha^2 + 2 \gamma^2 s}$.

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Maybe this question should be asked on MSE or even on mathoverflow. –  user8 Jul 1 '13 at 8:35