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Jun 27, 2015 at 13:48 vote accept Roozbe
Jul 6, 2015 at 16:47
Jun 26, 2015 at 15:19 comment added user16651 Why??? when $\sigma\rightarrow\infty$ then $\S_T\rightarrow\infty$
Jun 26, 2015 at 12:47 comment added q.t.f. I think the $\sigma\to\infty$ limit is wrong: should be $K$ as for Black-Scholes as long as $a(\sigma)$ doesn't grow too fast.
Jun 26, 2015 at 10:32 history edited user16651 CC BY-SA 3.0
deleted 5 characters in body
Jun 25, 2015 at 19:57 vote accept Roozbe
Jun 27, 2015 at 12:27
Jun 25, 2015 at 18:20 history answered user16651 CC BY-SA 3.0