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Have a look at ?dnorm, and rather use the standardized value as argument in your function, in addition to mean and sd:

a_<-dnorm((0.001-0.0001)/0.4, mean=0, sd=1)

Hope it helps

[EDIT] Likewise from ?dsgt

st<-(0.001-0.0001)/0.4

skewt<-dsgt(st, mu=0, sigma=1, lambda=0.1, p = 2, q=5, mean.cent=TRUE, var.adj=TRUE)

results in skewt=0.4302996 (close to your value)

For an explanation of the differences between Hansen(1994) and the recent references used in dsgt maybe it's worth posting a thread to Cross Validated (see link for related discussions)

Hope it helps

Have a look at ?dnorm, and rather use the standardized value as argument in your function, in addition to mean and sd:

a_<-dnorm((0.001-0.0001)/0.4, mean=0, sd=1)

Hope it helps

[EDIT] Likewise from ?dsgt

st<-(0.001-0.0001)/0.4

skewt<-dsgt(st, mu=0, sigma=1, lambda=0.1, p = 2, q=5, mean.cent=TRUE, var.adj=TRUE)

results in skewt=0.4302996 (close to your value)

For an explanation of the differences between Hansen(1994) and the recent references used in dsgt maybe it's worth posting a thread to Cross Validated (see link for related discussions)

Hope it helps

Have a look at ?dnorm, and rather use the standardized value as argument in your function, in addition to mean and sd:

a_<-dnorm((0.001-0.0001)/0.4, mean=0, sd=1)

Hope it helps

Have a look at ?dnorm, and rather use the standardized value as argument in your function, in addition to mean and sd:

a_<-dnorm((0.001-0.0001)/0.4, mean=0, sd=1)

Hope it helps

[EDIT] Likewise from ?dsgt

st<-(0.001-0.0001)/0.4

skewt<-dsgt(st, mu=0, sigma=1, lambda=0.1, p = 2, q=5, mean.cent=TRUE, var.adj=TRUE)

results in skewt=0.4302996 (close to your value)

For an explanation of the differences between Hansen(1994) and the recent references used in dsgt maybe it's worth posting a thread to Cross Validated (see link for related discussions)

Hope it helps

Have a look at ?dnorm, thus may I suggest you to specify mean and sd in your function as below:

a<-dnorm(0.001, 0.0001, 0.4)

a_<-dnorm(0.001, mean=0.0001, sd=0.4)

Hope it helps

Have a look at ?dnorm, and rather use the standardized value as argument in your function, in addition to mean and sd:

a_<-dnorm((0.001-0.0001)/0.4, mean=0, sd=1)

Hope it helps