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Apr 21, 2021 at 18:34 vote accept Parseval
Apr 18, 2021 at 15:12 vote accept Parseval
Apr 21, 2021 at 18:34
Apr 17, 2021 at 20:19 comment added ir7 Yes, $(t+h-j) - (t-i) = (s+h-j) - (s-i)=h+i-j$ is the common shift (for the covariance stationarity equality).
Apr 17, 2021 at 20:07 comment added Parseval Ah yes I missed that part. Will change. However the expectations you have written, that follows by the stationary property right? Nothing I need to prove.
Apr 17, 2021 at 19:11 history answered ir7 CC BY-SA 4.0