We assume that the inequality is given by
\begin{align*}
B > N C(K-1/N, T) - N C(K, T).\tag{1}
\end{align*}
The argument for the case with the inequality
\begin{align*}
B < N C(K, T) - N C(K+1/N, T)
\end{align*}
is similar.
$$$$
For the binary option,
\begin{align*}
\pmb{1}_{\{S_T \ge K\}} =
\begin{cases}
1, & \textrm{if } S_T \ge K,\\
0, & \textrm{otherwise},
\end{cases}
\end{align*}
while for the portfolio with payoff
\begin{align*}
X_T &= N\bigg[S_T-\Big(K-\frac{1}{N}\Big)\bigg]^+ - N (S_T-K)^+\\
&=
\begin{cases}
1, & \textrm{if } S_T \ge K,\\
N\bigg[S_T-\Big(K-\frac{1}{N}\Big)\bigg], & \textrm{if } K-\frac{1}{N} \le S_T \le K,\\
0, & \textrm{otherwise}.
\end{cases}
\end{align*}
Then, it is obvious that
\begin{align*}
\pmb{1}_{\{S_T \ge K\}} \le X_T,\tag{2}
\end{align*}
and, consequently,
\begin{align*}
B \le N C(K-1/N, T) -N C(K, T).
\end{align*}
$$$$
However, if (1) holds, we can then short the binary option, short $N$ units call option with strike $K$, and long $N$ units call option with strike $K-1/N$. We have a net profit
\begin{align*}
B - \big[N C(K-1/N, T) - N C(K, T)\big].
\end{align*}
Moreover, at maturity $T$, we have the portfolio payoff
\begin{align*}
X_T - \pmb{1}_{\{S_T \ge K\}} \ge 0,
\end{align*}
as per (2) above.