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We consider one factor driving model of fixed income product say short-term interest $r(t)=\lim\limits_{T\rightarrow t} R(t,T),$ $R(t,T)$ is yield i.e $$B(t,T)e^{(T-t)R(t,T)} = 1$$ Then we see several PDE of contingent claim

Zero-coupon bond $B(t,T)$ $$\dfrac{\partial B}{\partial t} + LB -r(t)B = 0$$ here $L$ is the differential operator in Feynman-Kac equation.

Swap of fixed rate $r^*$ $$\dfrac{\partial V}{\partial t} + LV -r(t)V + (r - r^*) = 0$$

Caplet at rate $r*$ $$\dfrac{\partial V}{\partial t} + LV -r(t)V + \min(r,r^*) = 0$$

Floorlet at rate $r*$ $$\dfrac{\partial V}{\partial t} + LV -r(t)V + \max(r,r^*) = 0$$

Here $r = r(t)$ and $V(t,T,r(t))$ is the value of contingent claim which is the function of $t$ and $r$ e.g, for zero-coupon bond $V=B.$

I couldn't understand when the dynamic of $r(t)$ is given, why there are some inhomogeneous terms in the Black-Scholes equation? Can some one explain one of later three?

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  • $\begingroup$ Can you please provide more background information? Where are these equations from? What is $V$ for each case? Is $r=r(t)$? $\endgroup$ – Gordon Feb 7 '17 at 20:56
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    $\begingroup$ @Gordon please see the updated version, and the question is in Duffy's book Finite Difference Methods in Financial Engineering Page276 $\endgroup$ – A.Oreo Feb 8 '17 at 1:57
  • $\begingroup$ See my answer to your another question. $\endgroup$ – Gordon Mar 19 '17 at 1:14
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Check out https://en.wikipedia.org/wiki/Feynman%E2%80%93Kac_formula, it is the $f(X_r,r)$ in the formula. For the swap you receive $(r-r^*) dt$ (assume notional of 1) which translates into your $f$ (inhomogeneous term).

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  • $\begingroup$ Conversely for a ZCB it is zero because you receive nothing (no cash flows) during the life of the ZCB. $\endgroup$ – noob2 Feb 8 '17 at 18:42
  • $\begingroup$ Sorry, you mean we receive the cash flow continuously? What I have learnt is for each time interval $[T_i,T_{i+1}]$ we receive the money at $T_{i+1}.$ Is it the discrete case? $\endgroup$ – A.Oreo Feb 9 '17 at 2:09
  • $\begingroup$ Hi @user26484. Thanks for your contribution, could please use the LaTeX formatting to make your comment clearer in the future? Thanks $\endgroup$ – Quantuple Feb 10 '17 at 9:33

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