Here is the proof that the limit of GARCH(1,1) $$\sigma_n^2 = \gamma V_L + \alpha u_{n-1}^2 + \beta\sigma_{n-1}^2$$ is equivalent to stochastic process of variance $$d V = \alpha(V_L - V) dt + \xi VdW.$$ We have already assumed return $u_{n-1}$ is $(0,\sigma_{n-1}^2)$-normal, then $u^2_{n-1}$ can't be normal. But author said that $$u^2_{n-1} = \sigma_{n-1}^2 + \sqrt{2}\sigma_{n-1}^2\varepsilon$$ where $\varepsilon$ is a random sample from a standard normal?
Options, Futures and Other Derivatives Solutions Manual Eighth Edition
page 171 Problem 22.14
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