My question is regarding the difference between risk neutral probabilities and stochastic discount factor? I am confused as to how are they related?

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    $\begingroup$ Risk neutral probabilities can always be expressed in terms of stochastic discount factors, but stochastic discount factors are not necessarily risk neutral. $\endgroup$ – David Addison Feb 25 '18 at 21:53
  • $\begingroup$ Maybe this related question also helps: quant.stackexchange.com/questions/8274/… $\endgroup$ – Quantuple Feb 26 '18 at 8:28

The risk neutral probability measure $Q$ is the true probability measure $P$ times the stochastic discount factor $M$ but rescaled so $Q$ sums to 1.

Simple derivation

For maximum simplicity, I'll work in a discrete probability space with $n$ possible outcomes. Everything goes through under measure theory in more general, infinite number of outcome probability spaces.

Let $\mathbf{x}$ be a vector denoting cashflows in those $n$ states. Let $\mathbf{p}$ be a vector denoting the probabilities of those $n$ states. Let $\mathbf{m}$ be a vector denoting the stochastic discount factor.

If a stochastic discount factor $\mathbf{m}$ exists, today's price of the future cashflow $\mathbf{x}$ is given by:

$$ f(\mathbf{x}) = \sum_{i=1}^n p_i m_i x_i $$

The basic idea behind risk neutral probabilities is to rescale $p_im_i$ and call it $q_i$. (Note $p_im_i$ is today's price for a cashflow of 1 in state $i$, a type of contingent claim known as an Arrow security). Define vector $\mathbf{q}$ as: $$ q_i = \frac{p_i m_i}{\sum_{j=1}^n p_j m_j}$$

Observe that $\mathbf{q}$ is also a probability vector since $\sum_i q_i = 1$. It's a vector of state prices rescaled so that $\mathbf{q}$ is a probability vector. Also note that risk free rate must satisfy $1 = \sum_i p_i m_i r$. Hence risk free rate $r = \frac{1}{\sum_i p_i m_i}$. Then: \begin{align*} f(\mathbf{x}) &= \sum_i \underbrace{p_i m_i}_{=\frac{q_i}{ r}} x_i \\ &= \frac{1}{r}\sum_i q_i x_i \end{align*}

Today's price of cashflow $\mathbf{x}$ is given by the expectation of $\mathbf{x}$ under the probability measure $\mathbf{q}$ discounted by the risk free rate.

The same logic goes through under measure theory (but you have a bit more formal mathematics with a Radon-Nikodym derivative etc...).

$$ \mathbb{E}^P[MX] = \frac{1}{r} \mathbb{E}^Q[X] \quad \quad \frac{dQ}{dP} = r M \quad \quad r = \frac{1}{\mathbb{E}^P[M]}$$

The whole idea of risk neutral pricing is incredibly simple: throw the stochastic discount factor into the probability measure.


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