# Replicating Portfolio / Complete Market / Attainable Claim

Attempt So Far:
1) First Part:
I have shown that the market is arbitrage-free since the only possible portfolio for which $$V_1^h\geq0 \$$ given that $$V_0^h=0 \$$ is $$h=(0,0,0)$$ and this clearly means that $$V_1^h=0$$ which contradicts (iii). Concluding that there is no arbitrage strategy.

2) Second part:

We can write $$\pmb{u_1}=(1.5,1.05)$$, $$\pmb{u_2}=(1,1.125)$$ and $$\pmb{u_3}=(1,1.11)$$ such that the Hadamard product (elementwise multiplication) of $$\pmb{u_{i}}_{,\ 1\leq i< \leq 3} \ \$$ and $$\ (S_0^1,S_0^2)$$ produces the possible $$(S_1^1,S_1^2)$$ found above with the given probabilities.

Fix a contingent claim $$X=F(S_1^1,S_1^2)$$ and I want to show that there exist $$h^*=(x^*,y^*,z^*)$$ that replicates X. Then $$V_1^{h^*}=\Phi(\pmb{u_{i}}_{,\ 1\leq i< \leq 3} \ )=X.$$ Thus, we've:

$$V_1^{h^*}= \left\{ \begin{array}{ll} \ 1.1x^* +15y^*+ 21S_0^2z^*=\Phi(\pmb{u_1}),& \text{with probability } \ 0.5 \\ 1.1x^* +10y^*+ 22.5S_0^2z^*=\Phi(\pmb{u_2}), &\text{with probability } \ 0.25 \\ 1.1x^* +10y^*+22.2S_0^2z^*=\Phi(\pmb{u_3}), & \text{with probability } \ 0.25 \end{array} \right.$$

$$\ \ \ \ \ \ \ \ \ \ \ \ \ = \left \{ \begin{array}{ll} \ 1.1x^* +1.5S_0^1y^*+ 1.05S_0^2z^*=\Phi(\pmb{u_1}),& \text{with probability } \ 0.5 \\ 1.1x^* +S_0^1y^*+ 1.25S_0^2z^*=\Phi(\pmb{u_2}), &\text{with probability } \ 0.25 \\ 1.1x^* +S_0^1y^*+ 1.11S_0^2z^*=\Phi(\pmb{u_3}), & \text{with probability } \ 0.25. \end{array} \right.$$

From here, I'm unsure of how to proceed. I'm not supposed to solve the system to find $$x^*, \ y^* \$$ and $$z^*$$ because the question clearly states that I shouldn't need to do that. That said, I'm not sure how to establish that the system above always has a solution without solving the system.

• For the second part you might want to use the 2nd Fundamental Theorem of Asset Pricing. That is, an arbitrage-free market is complete iff the risk-neutral measure is unique. (Reminder: market completeness means that every contingent claim can be replicated) So, if you can show that $Q$ is unique, you have shown that your claim can be replicated. May 13, 2021 at 8:27

## 1 Answer

It sounds like you have shown the first part, so I will concentrate on the second part.

We will use the Second Fundamental Theorem of Asset Pricing: An arbitrage-free market is complete if and only if the risk-neutral measure is unique.

Note that market completeness means that any contingent claim can be replicated by a portfolio. So, if you can show that $$Q$$ is unique, you have shown that your claim can be replicated.

To show $$Q$$ is unique, consider the price movements of each asset. We know that under $$Q$$ the discounted expected (under $$Q$$) price of the each asset must equal the current price of the asset. So

\begin{align} \mathbb{E}_Q[S_1^1] \frac{1}{1.1} &= 10 \\ \mathbb{E}_Q[S_1^2] \frac{1}{1.1} &= 20 \end{align}

So using the possible values that we are given for $$S^1_1$$ and $$S^2_1$$, we can write:

\begin{align} 15 q_1 + 10q_2 + 10q_3 &= 11 \\ 21q_1 + 22.5q_2 + 22.2q_3 &= 22 \\ q_1 + q_2 + q_3 &= 1 \end{align} where $$q_1, q_2, q_3$$ correspond to the $$P$$-probabilities $$0.5, 0.25, 0.25$$. Note that we have three equations with three unknowns. Hence, we have a unique solution, namely \begin{align} q_1 = 0.2, \; q_2 = 0.1\dot{3}, \; q_3 = 0.\dot{6} \end{align}

Thus, $$Q$$ in unique. This implies our market is complete (since you already showed it is arbitrage-free). Therefore, any contingent claim can be replicated (i.e the replicating portfolio exists).