This question is probably very simple and I'm just missing the easy solution but I'm a bit confused so I thought I might as well try ask here.
I've been given this question:
When I tried to calculate $p$ I got $p = 0.33$ (Let me know if this is incorrect), I obtained this using : $(e^{r_f} - d)/(u-d)$ so I had $(e^0-0.9)/(1.2-0.9)=0.33$
What I don't understand is the next part of the question, when it asks "is $p=0.5$ a risk-neutral probability?". This is confusing me because I've already calculated $p$ to be something else, since my $p$ is different does that mean that $p=0.5$ is not a risk-neutral probability and $p=0.33$ is the risk-neutral probability, right? Or have I got this all wrong?
Any help would be really appreciated just to clarify things for me.