The greeks, vanillas and digitals

Question 1: I know website’s like: https://optioncreator.com/ display the pricing and payoff graphs of regular plain vanilla puts and calls. I would like to know if there is any website that displays the payoff graph and pricing of digital options(a.k.a binary calls or put)?

Purpose: Read a post on quant: Delta hedging on Barrier/Digital Options I learnt the greeks explode around the barriers.

Question 2: How would the price payoff graph(now, not at expiration) look like compared to a call spread. Let me explain.

Since I don’t have access to the digital payoffs, I would use the vanilla’s instead to explain my question. Ignore that there are two different strikes, assume just a single strike and there is a vertical barrier that represent that strike. Now the blue curve represent some time before expiration. I would like to know how the blue curve change when the barrier is crossed in digitals, due to the exploding greeks. Is it a drastic change like in picture 2 or changes the same way a vanilla would?

I am not sure if my second question is clear enough. Thanks ahead for answers or comments.

There is no difference in real world settings.

Market practitioners usually always price a digital as a tight call spread to capture skewness. For example, setting strikes at $$𝐾± = 𝐾 ±1/2𝑑𝐾,$$ in the limit of $$𝑑𝐾 → 0$$, the payoff approaches that of a digital. The reason is that a tight call spread, by using two vanilla options, effectively accounts for the volatility smile skew. A helpful post can be found here.

Theoretically, an infinitesimally small spread will price a digital exactly. However, the required notional becomes increasingly large. Therefore, there is a trade-off between being partially unhedged and liquidity considerations. Why? A digital call is replicated by buying a call at the lower strike and selling a call at the upper strike. Think for example of EURUSD (CCY1CCY2 to make it generic), with notional in EUR and payment in USD. A call spread will pay $$max(0, 𝑆_t − 𝐾_{𝑙𝑜𝑤𝑒𝑟}) − min(0, 𝑆_𝑡 − 𝐾_{𝑢𝑝𝑝𝑒𝑟})$$.

Specifically, the call spread is implemented as $$𝐷𝑖𝑔𝑖𝑡𝑎𝑙 = 𝐵𝑆(𝐾 +1/2𝑑𝐾, 𝑣𝑜𝑙(𝐾 +1/2𝑑𝐾)) − 𝐵𝑆(𝐾 -1/2𝑑𝐾, 𝑣𝑜𝑙(𝐾 -1/2𝑑𝐾))$$ with $$𝑑𝐾 = 1\%$$ for example, i.e. $$1/2𝑑𝐾 = 0.005$$. This notation shows that each strike has its own associated IVOL.

Below the lower strike, both options are OTM and expire worthless. The payoff is net zero above the upper strike. The area in between is not fully hedged and max profit equals the spread $$(𝑆_𝑡 − 𝐾_{𝑙𝑜𝑤𝑒𝑟}) − (𝑆_𝑡 − 𝐾_{𝑢𝑝𝑝𝑒𝑟}) = 𝐾_{𝑢𝑝𝑝𝑒𝑟} − 𝐾_{𝑙𝑜𝑤𝑒𝑟}$$. As long as CCY1 notional corresponds to the desired payoff in CCY2, any desired CCY2 payoff can be achieved by scaling the notional by $$1/𝑑𝐾$$. Therefore, the smaller the spread, the larger the notional.

If the underlying expires ($$𝑆_𝑒$$) in a small region $$𝐾 < 𝑆_𝑒 < 𝐾 + 𝜖$$ where $$𝜖 < 𝑑𝐾/2$$ then a seller of the digital has to pay out more than the hedge nets. If on the other hand, you set the strikes as $$𝐾_− = 𝐾-𝑑𝐾/2$$ and $$𝐾$$, then you make money regardless of where the underlying expires. This is called an over-hedge as illustrated in the figure below.

An over-hedge will cost more than the centred hedge on the barrier strike, because its payoff is strictly higher. That is a detail that is omitted in the figure above (the payoff diagrams would shift slightly, reflecting different costs for the premium).

Market makers frequently make the spread expiry and vol dependent. That is something you will typically not find at vendors like Bloomberg where spreads are simply kept constant for all digitals (like the $$1\%$$ illustrated above).

Theoretically, there exists another way of computing the value of a digital by using BS and adjust it numerically. $$Digital = BS_{dig} + cp ∗ BS_{vega} ∗ (dvol / dK)$$ where $$BS_{dig} = N(d2)$$
$$cp$$ is a call or put flag and
$$dvol / dK$$ is done numerically.

However, the preferred way of pricing digitals is via call spreads.

• Thanks you for that detailed answer. Yes to be sure I properly understand: It’s the increasing notional that cause the exploding greeks value at the boundaries? However the payoff(at anytime before expiration) Is not affected? @AKdemy
– user59094
Oct 6 '21 at 22:36
• Correct. The payoff (of a digital) is what you attempt to get / replicate with the call spread. Oct 6 '21 at 23:04
• Alright. Understood. Thanks again. @AKdemy
– user59094
Oct 6 '21 at 23:15