2
$\begingroup$

I am in a finance seminar and yesterday evening we had a lecture from a quant in a big bank about shortcomings of Heston model.

He was deriving the Heston PDE. (I know how to derive the Heston PDE when you set up a portfolio with cash and two options etc, but I have a problem with this new method.) He took a portfolio (self-financed for sure but he did not mention it) where we sold an option and we delta-hedge it with a "functional" quantity $\Delta$.

Noting $S$ the underlying and $V$ the variance he noted $U(t,S_t,V_t)$ the P&L of that portfolio. (He did not mention why that P&L is necessarily a function of $S$ and $V$, I guess it has to do with the fact that the Heston model is a markovian model, but I don't succeed it proving that the P&L must have this form. Same question for $\Delta$ I guess.)

After that he defined $$m(t,S_t,V_t) = \mathbf{E}\left[ \left. U(t,S_t,V_t) \right| \mathscr{F}_t \right]$$ and $$W(t,S_t,V_t) = \mathbf{V}ar\left[ \left. U(t,S_t,V_t) \right| \mathscr{F}_t \right]$$ and he said that he was going to derive PDE's satisfied by $m$ and $W$ and that from these PDE's he will then derive a PDE satisfied from the option's price.

To derive the PDE for $m$ he wrote that we start to write the dynamical programming principle as follows : $$m(t,S_t,V_t) = \mathbf{E}\left[ \left. \left( U(t+dt,S_t + dS, V_t + dV) + \Delta \left( dS_t - rS_t dt \right) \right) e^{-rT} \right| \mathscr{F}_t \right].$$

I don't understand at all what he meant by that.

$\endgroup$
0

1 Answer 1

1
$\begingroup$

I think it's hard for anyone that wasn't there to answer but if I had to guess I think he referred to Bellman's principle of optimality.

$\endgroup$
1
  • $\begingroup$ It is possible to formulate the Dynamic Hedging problem as a Control Theory problem (that is dynamic optimization over time). The goal is to choose $\Delta$ to maximize the discounted P&L of the hedged position. As mentioned by Bob Jansen the equation above can be derived from Bellman's Principle. $\endgroup$
    – nbbo2
    Dec 14, 2022 at 6:52

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.