Well, the main intuition of the Merton model is that a company's equity can be treated as a call option on its assets, thus allowing for the application of Black-Scholes option pricing methods. Let's consider a company that has assets $A_{t}$ financed by equity $E_{t}$ and a zero-coupon debt $B_{t}$ with face value K, and maturity T. At time of maturity T, we have:
$$
E_{T} =
\begin{cases}
A_{T} - K & \text{if } A_{T} > K \\
0 & \text{if } A_{T} \leq K
\end{cases}
$$
The reason being is that, at maturity T, debtholders would be paid the full face value K if the company's assets at T are greater than K, leaving to shareholders an equity amount of $A_{T} - K$. However, if $A_{T} \leq K$, then the company would default on its debt payment. In that case, since the debtholders have the first claim on what's left of the company's assets, the equityholders end up with nothing.
Then: $$ E_{T} = max(A_{T} - K, 0)$$
This is exactly the payoff of a call option on $A_{T}$ with a strike price K and maturity T. Therefore, the Black-Scholes option pricing methods can be applied, (assuming the asset value follows a GBM). By assuming that the equity value $E_{T}$ also follows a GBM, and by applying Ito's lemma, you can show that:
$$ \sigma_E E_t = \frac{\partial E_t}{\partial A_t} \sigma_A A_t $$
By substituting B-S call option delta, we obtain:
$$ \sigma_E E_t = N(d_1) \sigma_A A_t $$
In your own notation, at time t = 0, you set $A_0 = V_0$, then:
$$ \sigma_E E_0 = N(d_1) \sigma_V V_0 $$