Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 41821
0 votes

HEDGING WITH A PUT OPTION

A hedged stock position means that you own the stock and an option to reduce the risk. For owning the stock, you pay $S_0$ but receive $S_T$ in 3 months. Similarly, your option costs $1.50$ but will g …
Kevin's user avatar
  • 16.3k
2 votes
Accepted

Is the european put option an increasing function?

\end{align*} As an alternative to this answer, you may want to consider a classical no arbitrage argument and look at a portfolio which owns one put option with strike price $K_1$ and is short one put … It always boils down to the intuitive idea that a put option with larger strike price has a higher payoff and thus needs to cost more than a put option with a lower strike price. …
Kevin's user avatar
  • 16.3k
5 votes

Can increase in volatility reduce the price of a deeply in-the-money European put?

Note firstly that by the model-free put-call parity, put and call options have the same vega (i.e. changes in volatility affect put and call prices in an identical way). … should increase the call price'' but that would then also imply increasing put prices. …
Kevin's user avatar
  • 16.3k
7 votes
Accepted

Given $\mathbb{E}[X]$, $\mathbb{E}[\max(0,X)]$, and $\mathbb{E}[\min(0,X)]$, what is $\mathb...

I don't think one can answer your question. Suppose $X=e^{\mu+\sigma Z}$ is log-normal, i.e. positive. Thus, $\mathbb{E}[\max\{0,X\}]=\mathbb{E}[X] $ and $\mathbb{E}[\min\{0,X\}]=0$. From just knowing …
Kevin's user avatar
  • 16.3k