Disclaimer: I don't have any of these books, and I don't know for sure what the author is trying to say.
It sounds vaguely like Markowitz portfolio theory applied to returns relative to some benchmark instead of relative to the risk free rate?
Refresher on classic Markowitz portfolio theory.
I will use bold letters to denote vectors. $\boldsymbol{R}$ is a random vector denoting returns of risky assets and $r_f$ is the risk free rate.
- Define $\boldsymbol{\mu}_f = \operatorname{E}[\boldsymbol{R} - r_f]$
- Define covariance matrix $\boldsymbol{\Sigma}_f = \operatorname{Var}(\boldsymbol{R} - r_f)$
Portfolio weights for the tangency portfolio, the portfolio with the highest Sharpe ratio, are given by:
$$\mathbf{w} = \left( \frac{1}{\boldsymbol{1}' \boldsymbol{\Sigma}_f^{-1} \boldsymbol{\mu}_f}\right)\boldsymbol{\Sigma}_f^{-1} \boldsymbol{\mu}_f$$
For example, see derivation here.
A guess of what that the book is trying to talk about?
I don't have the book, and this is heavily extrapolation based upon that short passage.
- Let $R_b$ be a random variable denoting the return of some benchmark $b$.
- The author may be using alpha not in the Jensen's alpha sense (or stochastic discount factor alpha sense) but is calling returns above some benchmark $\boldsymbol{R} - R_b$ alpha?
- An information ratio
$\frac{\operatorname{E}[R_a - R_b]}{\operatorname{Var}(R_a - R_b)}$
is just a Sharpe ratio relative to some benchmark $R_b$ instead of
the risk free rate $r_f$.
- Define $\boldsymbol{\mu}_b = \operatorname{E}[\boldsymbol{R} - R_b]$ and $\boldsymbol{\Sigma}_b = \operatorname{Var}(\boldsymbol{R} - R_b)$. Then portfolio weights for the maximum information ratio portfolio would be the same $\mathbf{w} = \left( \frac{1}{\boldsymbol{1}' \boldsymbol{\Sigma}_b^{-1} \boldsymbol{\mu}_b}\right)\boldsymbol{\Sigma}_b^{-1} \boldsymbol{\mu}_b$.
Portfolio weights aren't proportional to $\boldsymbol{\mu}_b$ though. They aren't a scalar $\lambda$ times $\boldsymbol{\mu}_b$. You apply the linear transformation $\left( \frac{1}{\boldsymbol{1}' \boldsymbol{\Sigma}_b^{-1} \boldsymbol{\mu}_b}\right)\boldsymbol{\Sigma}_b^{-1}$ to $\boldsymbol{\mu}_b$ .