A security is currently trading at 100, and with 99% probability it will be at 110 tomorrow, and with 1% probability at 90. What is the value of an ATM call option today expiring tomorrow? Assume nil interest rates.
If you sell the option at $C$ and immediately hedge with $n$ shares of the underlying, you'll be left with $C - 100n$. Tomorrow your portfolio will be worth $C - 100n + 110n = C + 10n$ with 99% chance and $C - 100n + 90n = C-10n$ with 1% chance. In order for you to not lose or make money on selling the option, in the first case your portfolio must be worth 10, and in the second case 0. In other words, $C$ and $n$ are uniquely determined by
\begin{cases} C + 10n = 10 \\ C - 10n = 0. \end{cases} Solving yields $C = 5$ and $n = 1/2$.
On the other hand, one sees that there is a 99% chance the option has value 10 dollars tomorrow and a 1% chance it has no value, yielding $C = (10)(.99) = 9.90.$
Which is the correct valuation? Is the stock mispriced if we know there is a 99% chance of an upward movement?