I typically see people define realized variance as the squared difference in log returns, i.e. $$RVar = \frac{1}{T} \sum_{n=1}^N \log \left( \frac{S_{n}}{S_{n-1}} \right)^2$$ where $t_n - t_{n-1} = \delta t$ and $T=N\delta t$. This is obviously an unbiased estimator of log return variance given that the expected log return is 0. However, under geometric Brownian motion, we have $$\mathbb{E} \log \delta S = \delta t \left(\mu - \frac{1}{2} \sigma^2\right)$$ so $$\mathbb{E} \log \delta S^2 = \delta t \sigma^2 \delta t \left(\mu - \frac{1}{2} \sigma^2\right)$$ where $\mu$ is the growth rate of the underlying. This suggests that $RVol$ is not unbiased for $\sigma^2$, except in a special case. For now, assume $\mu$ is known to avoid statistical degrees of freedom issues. My questions are two:
(1) Why would one not attempt to correct for this bias in a volatility estimate?
(2) Estimating $\sigma$ is of special interest in options. Under risk-neutral measure, $\mu = r$ the risk-free rate. Which would be more correct to use in our unbiased volatility estimate? It seems suspect that volatility stays constant under change of measure, yet the choice of measure effects our volatility estimate.