0
$\begingroup$

How are interest rate and dividend functions integrated over time in practice?

For example, what does it mean in practice to discount a current price by $e^{\int_{t_m}^{T}r_s ds }$ where $r_s$ is the interest rate function or $e^{\int_{t_m}^{T}\delta_s ds }$ where $\delta_s$ is the dividend fuction.

$\endgroup$
0

1 Answer 1

1
$\begingroup$

For a fixed interest rate or dividend payment/yield, integrating the function becomes:

$\large{P_T = } \Large{e^{\int_t^T r_s ds} = \Large{e^{r_s (T - t)}}}$

$P_T$ is usually understood to be the future value of a zero-coupon bond with a face value of \$1. The present value, $P_t$, is simply then:

$\large{P_t = } \Large{e^{\int_t^T -r_s ds} = \Large{e^{r_s (t - T)}}}$

If $r_s$ is a function, then that must be accounted for in the integration. For complex functions, it is common to estimate the quantity through discretization techniques. When discounting a discrete function, a product function may be used:

$\large{P_T=\prod_{t}^T(r_s + 1)}$;

for fixed $\large{r_s}$, $\large{P_T \to (r + 1)^{(T - t) + 1}}$

If $r_s$ is not a deterministic function (i.e., it is stochastic), we must now take the expectation under some risk-neutral measure, $\mathbb{Q}$, where the price of a zero-coupon bond at time, $T$, equals:

$\large{ \mathbb{E}[ P_T] = \mathbb{E^Q} [e^{\int _{t}^{T}r_{s}\,ds}|{\mathcal{F}}_{t}]}$

where $\mathcal{F_t}$ is a natural filtration process.

There exist many methods and models by which to express the expectation of a stochastic interest rate. E.g.: Cox-Ingersol-Ross; Ho-Lee; Hull-White; Merton; etc... The "best" model just depends on what you're trying to do.

When dividends are also present, it is common and mathematically convenient to assume they are a fixed proportion of $P_t$. The effect of proportional dividend is often thought of a exerting a "decay" on future value; it is thus common for pricing models to take the expectation of a "forward" value, $F_t$.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.