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Following is given,

$dB(t)=rB(t)dt$

$dS(t)= (r-\delta)S(t)dt+\sigma S(t)dW(t)$

where, $r$ is the risk-free interest rate, $\delta$ the continous dividend yield $\sigma$ is the stock asset volatility and $W$ brownian motion.

By solving the SDE that is the money account B and applying Itô's lemma on the stock dynamic S I get,

$B(T)=e^{r(T-t)}$ and

$S(T)=S(t)e^{(r-\delta-\sigma^2/2)+\sigma(W(T)-W(t))}$

I know further that the No Arbitrage price is defined as,

$\Pi(t;X)=1/B(T)*E^Q_t[max[B(T),S(T)]]$


Question

Can I somehow cancel out B(T) since it is deterministic? How do I calculate the expectation of a maximum with a brownian motion W?

I am new to probability theory, financial mathematics and stochastic calculus. Would appreciate step-wise guidance. Thank you!

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1 Answer 1

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$\max(B_T,S_T)=\max(0,S_T-B_T)+B_T,$ so this is just a call option (with strike $B_T$) plus $B_T.$

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  • $\begingroup$ Hi, is it an integral that i have to solve afterwards? $\endgroup$
    – Dreason94
    Commented Dec 11, 2019 at 20:56
  • $\begingroup$ Yes, an integral, but Black and Scholes already solved it in 1973 ;) . Just use the Black Scholes formula for a call with $B_T$ replacing the strike price $X$ and with an additional $B_T$ term added. $\endgroup$
    – Alex C
    Commented Dec 11, 2019 at 21:11
  • $\begingroup$ Thank you very much. Say that it would be an exam question. Can I just type out N[d_1] and N[d_2] and just say the are normal cumulative density functions? $\endgroup$
    – Dreason94
    Commented Dec 11, 2019 at 22:04

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